Question

25x^-2 - 10x^-1 + 1=0. FIND 'X'

Answer 1

Answer:

x=5

Step-by-step explanation:

Firstly:

\frac{25}{x^2}-\frac{10}{x}+1=0

Then, multiplying by LCM=x², we get:

\frac{25}{x^2}x^2-\frac{10}{x}x^2+1\cdot \:x^2=0\cdot \:x^2

Now, by simplifying it, we get:

25-10x+x²=0

Arranging it:

x²-10x+25=0

a=1,\:b=-10,\:c=25:\quad x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:25}}{2\cdot \:1}

x=5.

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hence, x=5

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i hope it will helps you friend