Question

25x^4-20x^2+4=0 solve for x

Answer 1

hey friend

here your answer
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$25 {x}^{4} - 20 {x}^{2} + 4 = 0 \\ \\ \\ \\ d = {b}^{2} - 4ac \\ \\ \\ a = 25 \\ b = - 20 \\ c = 4 \\ \\ d = {( - 20) }^{2} - 4(25)(4) \\ \\ \: \: \: = 400 - 400 \\ \\ \: \: \: = 0 \\ \\ \\ {x}^{2} = \frac{ - b + \sqrt{d} }{2a} \\ \\ \: \: \: \: \: \:= \frac{ - ( - 20) + \sqrt{0} }{2 \times 25} \\ \\ \: \: \: \: \: \: = \frac{20}{50} = \frac{2}{5 } \\ \\ \: \: \: \: \: \: \: so............ \\ \\ \\ \\ \: \: x = \sqrt{ \frac{2}{5} } \: \: \: \: or \: \: x = \frac{ \sqrt{2} }{ \sqrt{5} } \\ \\ \\ \\ \: \: \: \: hope \: it \: helps \: you$