25x2-x(m-2)-1=0 find the m
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The roots of the equation are
( (m-3) (+/-) ((m-3)^2 - 4m)^(1/2) )/2 > 0
So, (m-3)^2> (m-3)^2 - 4m
So, 4m>0
Implies, m>0
Also, (m-3) ^2>4m
So, m^2-6m+9>4m
So, m^2-10m+9>0
(m-9)(m-1)>0
So, m>9 or m<1
So, the range of m is (0,1)U(9,infinity)
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redhatleet:
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