Question

26. એક સમાંતર શ્રેણીનું 12મું પદ 4 અને 20મું પદ - 20 છે, તો તે શ્રેણીનું nમું પદ શોધો.

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Answer 1

Solution:

Let

"a" → first term of the A.P. = 4

"l" → last term of the A.P. = 31

"n" → no. of terms in the A.P.

$⟹420=2n×35 \\ \implies n = \frac{420 \times 2 }{35} \\ ⟹n=35420×2 \\ \implies n = \frac{60 \times 2 }{5} \\ ⟹n=560×2 \\ \implies \bold{n = 24} \\ ⟹n=24</p><p></p><p>$

Answer 2

Step-by-step explanation:

Let

"a" → first term of the A.P. = 4

"l" → last term of the A.P. = 31

"n" → no. of terms in the A.P.

• ⟹420=2n×35
• ⟹n= 35420×2

• ⟹n=35420×2
• ⟹n= 560×2

• ⟹n=560×2
• ⟹n=24
• ⟹n=24

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