Question

(2⁶ + 2‐³) × 2¹⁴ = 2x find the valure of x class 7th sum exponents and power​

Answer 1

Answer:

The value of n is 10.

Step-by-step explanation:

Given : Expression (\frac{2}{3})^3\times (\frac{2}{3})^5=(\frac{2}{3})^{n-2}(

3

2

)

3

×(

3

2

)

5

=(

3

2

)

n−2

To find : The value of n in each of the following expression ?

Solution :

Expression (\frac{2}{3})^3\times (\frac{2}{3})^5=(\frac{2}{3})^{n-2}(

3

2

)

3

×(

3

2

)

5

=(

3

2

)

n−2

Using exponent identity, a^b\times a^c=a^{b+c}a

b

×a

c

=a

b+c

(\frac{2}{3})^{3+5}=(\frac{2}{3})^{n-2}(

3

2

)

3+5

=(

3

2

)

n−2

(\frac{2}{3})^{8}=(\frac{2}{3})^{n-2}(

3

2

)

8

=(

3

2

)

n−2

Comparing the base,

8=n-28=n−2

n=10n=10

Therefore, the value of n is 10.

Answer 2

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