26.8 g Na2SO4.nH2O has 12.6 g water.find the value of n
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Na2SO4 * n H2O
Molar mass of salt = (142 + 18n)
Mass of water = 12.6 / 26.8 x (142 + 18n)
18 n = 12.6/26.8 (142 + 18n)
n = 7
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Molar mass of Na₂SO₄ = 142 g
Molar mass of water = 18 g
Molar mass of given salt = 142 + 18 n
Mass of water =
482 . 4 n = 12.6(142 + 18n)
482.4 n = 1789.2 + 226.8 n
255.6 n = 1789 . 2
n = 1789.2/ 255.6 = 7
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Molar mass of Na₂SO₄ = 142 g
Molar mass of water = 18 g
Molar mass of given salt = 142 + 18 n
Mass of water =
482 . 4 n = 12.6(142 + 18n)
482.4 n = 1789.2 + 226.8 n
255.6 n = 1789 . 2
n = 1789.2/ 255.6 = 7
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