Math, asked by ranjanamanojbafna, 9 months ago

26. A bag contains 4 blue. 4 red, 6 yellow and 10 white marbles. What is the probability of drawing the
following? Which of these is a certain event?
(i) A blue marble
(ii) A yellow marble
(iii)/ red marble
(iv) A white marble
(v) A blue marble or a yellow marble
(vi) A red marble or a white marble​

Answers

Answered by unnati9923
16

Answer:

n(s)=24.

probability of getting blue marble :let it be event A

n(A)=4

p(A)=n(A)/n(s)

= 4/24

=1/6

...

event B :yellow marbles

n(B)=6

p(B)=6/24=1/4

event c:red marble.

n(c)=4

p(c)= 4/24=1/6

event d :white marble

n(d)=10

p(d)=10/24

event e: a blue marble or a yellow marble .

n(e)=14

p(e)=14/24=7/12

event f:a red or a white .

n(f) =16

p(f)=16/24

=2/3

it take a long time to type plz mark as brainliest

Answered by vishwarms
3

Answer:

24

Step-by-step explanation:

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