Question

26. A bag contains 5 red and 3 black balls and another bag contains 2 red and 6 black balls.​

Answer 1

P(Red balls)=7 /16

=0.43

P(Black balls)=9/16

= 0.57

Answer 2

Answer:

Step-by-step explanation:

1. The first bag is chosen; the probability is 1/2. AND the probability of drawing a red ball is 5/8; AND the probability of drawing a black ball after that is 3/7. So, the probability is 1/2 * 5/8 * 3/7 = 15/112.

2. OR, the probability of drawing a black ball first is 3/8 AND drawing a red ball after that is 5/7. The probability in this case is 1/2 * 3/8 * 5/7 = 15/112.

3. The probability of drawing different coloured balls in the first case = 1 + 2 = 15/112 + 15/112 = 15/56.

Second case:

1. The second bag is chosen; the probability is 1/2. AND the probability of drawing a red ball is 4/9; AND the probability of drawing a black ball after that is 5/8. So, the probability is 1/2 * 4/9 * 5/8 = 20/144.

2. OR, the probability of drawing a black ball first is 5/9 AND probability of drawing a red ball after that is 4/8. The probability in this case is 1/2 * 5/9 * 4/8 = 20/144.

3. The probability of drawing different coloured balls in the second case = 1 + 2 = 20/144 + 20/144 = 20/72.

The total probability of drawing different coloured balls after considering both the cases = First case OR second case = 15/56 + 20/72 = 275/504 = 0.546