Physics, asked by LearningAims, 8 months ago

26. A body A of mass 20 kg is moving with
a velocity 1m/s, another body B of mass 1
kg is moving with a velocity of 20 m/s. The
ratio of K.E. of A and B is
(2 Points)
1:20
20:1
1:1​

Answers

Answered by jprateek413
0

Hey I will tell u the answer

mA= mass of body A =20kg

vA is velocity of the body A=1m/s

k.E1 is your kinetic energy of body A=1/2mA(vA)²

=1/2 x 20 x (1)²

=10 joule

KEA=10 joule

now vb is velocity of b is 20m/s

and mb is mass of b is 1kg

keb is kinetic energy of b =1/2*1*(20)²=200

ratio of keb to KEA is 200/10= 20:1

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