Question

26) A boy's age is one-fourth that of his father.
After 24 years the boy will be half the age of
his father. Find their present ages.
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Answer 1

Answer:

Boy age at present=x/4

Present age of father=x

By the given data

x/4+24=x+24/2

[96+x/4]2=x+24

96+x=2(x+24)

96-48=2x-x

x=48

Present age of father =x=48 years

Present age of the boy = x/4=48/4=12 years

Hope it helps u...

Answer 2

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Given :-

A boy  age is one-fourth that of his father.  After 24 years the boy will be half the age of  his father.

To Find :-

Present ages

Solution :-

Let the present age of father be x

Age of son = x/4

Now

x/4 + 24 = x + 24/2

x + 96/4 = x + 24/2

2(x + 96) = 4(x + 24)

2x + 192 = 4x + 96

4x - 2x = 192 - 96

2x = 96

x = 96/2

x = 48 years

Age of son = 48/4 = 12 years

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