Question

26. A car is moving with constant velocity 10 m s-!. When brakes are applied it comes to half in 1.2 s. What is the retardation of the car? [0.83 ms?​

Answer 1

Explanation:

A car is moving with a speed of 40 m/s. On applying brake, it comes to rest at 20 s. What is the distance between the distance covered by the car before it stops?

Given

initial velocity (u) = 40 m/s

Final velocity ( V) = 0 m/s

Time taken ( T ) = 20 second

now first we find the retardation after then we find distance

V= u + at

or, a =( V- u)/T

or a = -40/20

or a = - 2 m/s²

now V² = u² + 2as

or S = - (40)²/ 2 (-2)

or S = 400 m

hence distance coveres before come to rest is 400 m.