Question

26. A particle is dropped from height 125m.
(i) After how much time does the stone strike the earth?
(ii) Average velocity of the stone during this interval.
Ans.(i) 5 s (ii) 25 m/s.​

Answer 1

s = ut + 1/2at^2

u = 0

a = g = 9.8m/s^2

t = √(2s/a)

t = √2*125*9.8

t = 49.5 sec

Answer 2

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