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A particle of mass m is taken from position
to position B along the circular path by a Force
F, where magnitude of Fis constant and it is
always directed towards point B what will be
the work done by the Force F. Here radius of
Track is R.
(1) FR
(3) F(V2R)
(4) None
F-3/17
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Answer:
Work done would be zero
Explanation:
Here we are given that the particle of mass m is moving with a constant Force, with respect to its magnitude. This means that, there is no acceleration or the particle is moving with a uniform velocity. In uniform circular motion, only the direction of the velocity is changing, because the force is at right angles to the movement. Since the speed (i.e. the magnitude of the velocity) is constant, no work is being done and the energy remains constant.
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