Question

26. A railroad car of mass M is at rest on frictionless rails
when a man of mass m starts moving on the car towards
the engine. If the car recoils with a speed v backward
on the rails, with what velocity is the man approaching
the engine?
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Answer 1

Answer:

Hey!

Here's ur answer:

Explanation:

=> - mv+mv0-mv=0

=> v0=v(m+M)/m

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Answer 2

Answer:

mass of a car = M

mass of a man = m

initial velocity of a car was u1 = 0m/s .

let man's velocity be u m/s .

the car acquires a speed of v m/s .

*ACCORDING OF CONSERVATION OF LINEAR MOMENTUM :

mu +mu1 (m+M)V. {as the man is in the car having velocity v and net mass is (m+M)

mu = (m+M)V

or

u ( initial velocity of man) = [(m+M)V]/u

or

v [1+ M/m]

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