Question

26. A right circular cylinder has radius 14 cm and
height 40 cm. One conical part is cut from each
bases of cylinder. Radius and height of each
conical part is 9cm and 12cm. Find TSA of
remaining solid?​

Answer 1

Answer:

1320

Step-by-step explanation:

The diameter of the cylinder given in the question is 24 m.

a tent cylindrical in shapeRadius (R) = 12/2 = 12 m

The height of the Cylindrical part (H1) given in the question is 11m

So, Height of the cone part (H2) = 5 m

Now,

Vertex of the cone above the ground = 11 + 5 = 16 m

Curved Surface area of the Cone (say, S1) = πRL = 22/7 × 6 × L

Where,

So,

Curved Surface Area of Cone (S1) = 22/7 × 12 × 13               .... E.1

Curved Surface Area of Cylinder (S2) = 2πRH1

S2 = 2π(12)(11) m2              .... E.2

To find the area of Canvas required for tent

S = S1 + S2 = E.1 + E.2

S = 22/7 × 12 × 13 + 2 × 22/7 × 12 × 11

S = 490 + 829.38

S = 1319.8 m2

S = 1320 m2

Hence, the total Canvas required for tent (s) = 1320 m2

Answer 2

Answer:

1320

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