Physics, asked by sanketaich1234, 7 months ago

26. A transformer has full load copper loss
of 400 W. The copper loss at half full-load
will be
(A) 200 W
(B) 100 W
(C) 50 W
(D) none of these​

Answers

Answered by mansi3608
0

Answer:

copper loss is proportional to square of load current. Al half load, load current becomes half as voltage remains same, so copper loss will become (1/2)^2 times of full load copper loss or 1/4 ×1600=400watt.

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