Question

26. ABC is an isosceles triangle right angled at C. prove that AB' =2 AC ?​

Answer 1

Step-by-step explanation:

GIVEN :

LET AB= a

BC = b

CA = c

a= b (ISOSCELES TRIANGLE)

TO PROVE :

BY PYTHAGORAS THEOREM

${c}^{2} = {a}^{2} + {b}^{2} \\ \\ {c}^{2} = 2 {b}^{2} \: \: \: \: \: (because \: \: \: \: a = b) \\ \\ or \: \: \: \:$

${</p><p>AB}^{2} = 2 {</p><p>AC</p><p></p><p>}^{2}$

HENCE PROVED