Question

26.An element X (atomic number 17) reacts with an element Y (atomic no 20) to form a
divalent halide.
(a) where in the periodic table are elements X and Y placed ?
(b) Classify X and Y as metals, non metals, or metalloids.
(c) What will be the nature of the oxide of element Y?
(d) Identify the nature of bonding in the compound formed.
(e) Draw the electron dot structure of the divalent halide.​

Answer 1

Answer:

(a)X lies on the left hand side of the periodic table.Its periodic number is 3 and group number is 17.

Y lies on right hand side of the periodic table.Its periodic number is 4 and group number is 2

(b)X is a non metal while Y is a metal

(c)the nature of oxide of y is basic oxide.

(d)They has ionic bonding

(e) sorry mate i don't know how to post pic...but i can give u hint..u can do it by sharing of electrons just like we form in nacl...hope it helps u

Answer 2

As the atomic numbers are given so

Element X is CHLORINE (Cl)

Element Y is CALCIUM (Ca)

In the periodic table X is placed in 17th group and 3rd period.

Y is placed in 2nd group and in 4th period.

X is a non metal as it is a halogen.

Y is metal as it lies between 1-12th group.

Nature of oxide of Y will be basic as it is a metal.

Nature of bonding will be IONIC BOND.

Hey buddy draw the electron dot structure of CaCl2 as

Ca = 2,8,8,2

Cl= 2,8,7