Question

26. An object is placed at 0.2 m from a convex lens of 38
focal length 0.15 m. Find the position of the image.
Ans. 0.6 m, behind the lens.​

Answer 1

Answer:

your answer is:-

0.6m, behind the lens

Answer 2

Given:

Image distance (u) = - 0.2 m

Focal length (f) = 0.15 m

To Find:

Image distance (v)

Answer:

Lens formula:

$\bf \dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}$

By substituting values in the formula we get:

$\rm \implies \dfrac{1}{v} - \dfrac{1}{( - 0.2)} = \dfrac{1}{0.15} \\ \\ \rm \implies \dfrac{1}{v} + \dfrac{1}{ 0.2} = \dfrac{1}{0.15} \\ \\ \rm \implies \dfrac{1}{v} = \dfrac{1}{0.15} - \dfrac{1}{0.2} \\ \\\rm \implies \dfrac{1}{v} = \dfrac{4 - 3}{0.6} \\ \\ \rm \implies \dfrac{1}{v} = \dfrac{1}{0.6} \\ \\ \rm \implies v= 0.6 \: m$

As, the image distance is positive it means that image is formed behind the lens.

$\therefore$ $\boxed{\mathfrak{ Image \ distance \ (v) = 0.6 \ m, \ behind \ the \ lens}}$