26 both please help me geniuses??
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please mark it brainliest
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Answer:
secθ + cosecθ
Step-by-step explanation:
(a)
Given: (sinθ + cosθ)(tanθ + cotθ)
= (sinθ+cosθ)[sinθ/cosθ + cosθ/sinθ]
= (sinθ + cosθ)[sin²θ + cos²θ/sinθ cosθ]
= (sinθ + cosθ)[1/sinθ cosθ]
= (sinθ + cosθ)/(sinθ cosθ)
= (sinθ/sinθ cosθ) + (cosθ/sinθ cosθ)
= (1/cosθ) + (1/sinθ)
= secθ + cosecθ
(b)
Here, I am writing θ as A.
(i)
(ii)
∴ (i) = (ii) = 1/secA - tanA
Hope it helps!
komalsingrajput:
sir
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