Question

26. (cos² 32° + cos² 58°) /(sin² 59° + sin² 31°) का मान ज्ञात कीजिए।

Answer 1

$\huge\boxed{\underline{\underline{\green{Solution}}}} </p><p></p><p>$

$\displaystyle \: \frac{(cos² 32° + cos² 58°)}{(sin² 59° + sin² 31°)}$

$= \displaystyle \: \frac{cos² 32° + cos² (90° - 32°)}{sin² 59° + sin² (90° - 59°)}$

$= \displaystyle \: \frac{(cos² 32° + sin² 32°)}{(sin² 59° + cos²59°)}$

$= \frac{1}{1}$

$= 1$

$\displaystyle\textcolor{red}{Please \: Mark \: it \: Brainliest}</p><p>$

Answer 2

Answer:

Answer is 1

Step-by-step explanation:

cos²32+cos²58/sin²59+sin²31

=sin²58+cos²58/sin²59+cos²59

=1/1

=1

Thanku