Question

26. During Electrolysis of an aqueous solution of Sodium Chloride (brine), three (3) products NaOH, Cl2 and H2 are obtained. In this experiment, which of the following statement is correct?


A. H2 is released at Cathode, Chlorine at the Anode and NaOH is formed near the cathode.

B. Cl2 is released at the Cathode, H2 at anode and NaOH is formed near the cathode.

C. NaOH is formed near Anode, Chlorine at the Cathode and H2 is released at the cathode.

D. NaOH is formed near cathode, H2 at the Anode and Cl2 is released at the cathode.

which option is correct.​

Answer 1

Answer:

option A is correct

Explanation:

as u can see in the attachment

H₂ is released at Cathode, Cl⁻ at the Anode and NaOH is formed near the cathode.

Here's a trick to remember anode and cathode are negative or positive,

ACP = Anode, cation, positive

CAN = Cathode, anion, negative

Answer 2

During electrolysis of an aqueous solution of sodium chloride (brine) the products obtained are -

$H_2$ is released at the cathode, Chlorine at the anode, and NaOH is formed near the cathode. (OPTION A)

Explanation

ELECTROLYSIS OF SODIUM CHLORIDE (BRINE) -

• Brine is the solution of sodium chloride and water.
• The electrolysis process involves an electric current to facilitate chemical change.
• At the anode, chloride is oxidized to chlorine, and at the cathode, water to reduced to hydroxide and hydrogen gas.
• The ion-selective membrane allows the sodium ions to flow freely.
• The sodium ions combine with hydroxide ions to form sodium hydroxide.
• The reactions involved are -

CATHODE                 $H_2O + 2e^-$ → $H_2 + OH^-$

ANODE                      $Cl^-$ → $\frac{1}{2} Cl_2 + e^-$

OVERALL REACTION,

$NaCl(aq) + H_2O(l)$ → $Na^+(aq) + OH^-(aq) + H_2(g) + \frac{1}{2}Cl_2(g)$

• Sodium hydroxide holds commercial importance in soap and detergent industries.