Question

26. Evaluate :
2 sin 68°/cos22°- 2 cot 15°/tan 75°-3 tan 40° tan 45º tan 50°​

Answer 1

Answer:

The answer is 1.

Step-by-step explanation:

Before solving, the following formulas must be kept in mind.

sin x = cos (90-x)

tan x = cot (90-x)

tan(x)×cot(x) = 1

sin 68° = cos 22°

cot 15° = tan 75°

tan 45° = 1

tan 50° = cot 40° & tan 70° = cot 20°

The problem then reduces to 2 sin 68°/sin 68° - 2 cot 15°/5 cot 15° - 3 tan 20° tan 40° cot 40° tan 40°/5 = 2-2/5-3/5 = 2-1 = 1.