Question

26. Find the area of the following quadrilaterals: ​

Answer 1

Answer:

Area of the triangle Abc = 1/2 × b × h

= 1/2 × 6 × 3 = 18 ÷ 2 = 9 cm square.

Area of the triangle ADC = 1/2 × b × h

= 1/2 × 6 × 5 = 30 ÷ 2 = 15 cm square

Total area of the quadrilateral = Area of triangle ABC + Area of triangle ADC

= 9 + 15 = 24 cm square

Answer 2

Answer:

Given ➡

Base= 6cm

Height 1= 3cm

Height 2= 5cm

So,

$\frac{1}{2} \times (h \: 1 + h \: 2) \times base\\ = \frac{1}{2} \times (3 + 5) \times 6 \: cm \\ = \frac{1}{2} \times 8 \times 6 \\ = 24 \: {cm}^{2}$

Therefore, Area = 24cm^2