Question

26. Find the area of the quadrilateral ABCD in which diagonal AC is 15 cm and length ofperpendicular from B and D on AC be 3 cm and 5 cm.​

Answer 1

60 sq cm

Step-by-step explanation:

the diagonal divide the quadrilateral into 2 triangles

∆ABC and ∆ADC

area of ∆ABC = 1/2 × AC × h

= 1/2 × 15 × 3

= 7.5 × 3

= 22.5 sq cm

area of ∆ADC = 1/2 × AC × h

= 1/2 × 15 × 5

= 7.5 × 5

= 37.5 sq cm

area of quadrilateral ABCD

= ar ∆ ABC + ar ∆ ADC

= 22.5 + 37.5

= 60 sq cm

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