Question

26. Find the equation of the ellipse whose axes are along the coordinate axes, foci at (0, 4) and eccentricity
is 4/5​

Answer 1

Answer: x²/9 +y²/25 =1

Step-by-step explanation:

Foci is given by (0, ±ae) for ellipse whose major axis is along y axis the find a

ae=4

a4/5=4

a=5

Then we know that

a²-b²=c²

e=c/a

Now

e=√(a²-b²)/a

Simplifying we get b=3

For ellipse along y axis general formula is

x²/b² +y²/a²=1

Hence the answer

x²/9 +y²/25 =1