Question

26 - find the largest six -digit numbers exactly
divisible by 36, 24, 48, and 128.​

Answer 1

Answer:

999936

Step-by-step explanation:

Largest 6 digit number = 999999

LCM of 36, 24, 48, 128 =>

2| 36, 24, 48, 128

2| 18, 12, 24, 64

2| 9, 6, 12, 32

2| 9, 3, 6, 16

3| 9, 3, 3, 8

| 3, 1, 1, 8

LCM = 2 × 2 × 2 × 2 × 3 × 3 × 8 = 1152

Now

When 999999 ÷ 1152 we get remainder = 63

&

999999 - 63 = 999936

So 999936 is the largest six digit number exactly divisible by 36, 24, 48, 128