26. If 5m/s and 10m/s are the velocities of a body
having a uniform acceleration in some
time interval, what will be its average
velocity?
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Answer:
We know average velcity=total distance/total time
Let distance be x
So, for first velocity, time taken=x/5
and for the second velocity, time taken=x/10
now average velocity=x+x/(x/5+x/10)
=2x/(2x+x/10)
=2x/3x/10
=2x*10/3x
=20/3m/s
=6.66m/s
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