Question

26. If cosec (A + B)=1 and cosec (A-B)=2,0° <(A+B) <= 90° and A>B
then find the vaues of:
tan Atan B
(i) sin Acos B+cos Asin B ii) tanA - tan B / 1+tanA tanB
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Answer 1

Answer:

sec(A-B)=2 sec(A-B)=sec60 A-B=60 . ....................(ii) solving (i) and (ii). A=75 and B=15 we know the identity that tanA+tanB/1-tanAtanB=tanA+B)