Question

26.
If sin(A+B) = 1 and cos(A-B)=√3/2

then​

Answer 1

Step-by-step explanation:

sin(A+B)=1

sin(A+B)=sin 90

A+B=90 ——equation -1

cos(A-B) =√3/2

cos(A-B) = cos30

A-B=30——equ.2

From equation 1 and 2

A+B=90

A-B=30

——————

2A=120

A=120/2

A=60

on putting the value of A in equ 1

A+B=90

60+B=90

B=90-60

B =30

so ,

A=60

B=30