Question

26. If specific heat capacity of water is 4200 Jkg–1°C-1. The amount of heat energy
required to prepare a water bath of 20 kg from cold water at 10°C to warm water at
40°C is
​

Answer 1

Answer:

Heat Capacity =Specific heat×mass

=4200J/Kg

o

C×10

=42000J

=42kJ

Answer 2

2520000J

$\huge \purple{ \boxed{ \blue{ \: \: \: SOLUTION} \: \: \: \: \: \:}}$

$\sf{ \tt{Temperature \: raise \: is \to40 - 10 = 30 \degree c}}$

$\tt heat \: required \to \red{ms \triangle T}$

$\tt = 20 \times 4200 \times 30 = \huge{ \underline{ \overline \orange{252000J}}} {\frak \pink{ \: \: \: ANSWER!}}$