Question

26. If the simple interest on Rs. 750 is less than the interest on Rs. 845 at 10% p.a. S.I. by Rs. 57. Find the
time
(a) 4 years
(b) 5 years
(5) 6 years
(d) None
Omd​

Answer 1

(845×10/100×t)-(750×10/100×t)=57

84.5t-75t=57

9.5t =57

t=6

Ans:6years.

Answer 2

Concept: Simple interest is calculated on a loan's principle amount or the first deposit into a savings account. Simple interest doesn't compound, thus an account holder only earns interest on the principal and a borrower never has to pay interest on previously accumulated interest.

Given: Principal (for first case) = Rs.750 ;

           Principal (for second case) = Rs. 845

           Rate = 10% p.a.

           Difference between the interests = Rs.57

To find: the time

Solution: let the time be 't'

Now, considering the first case

P = Rs.750

R = 10%

T = t

$I = \frac{PRT}{100}$

$I = \frac{750*10*t}{100}$

I = 75t

Now, considering the second case

P = Rs.845

R = 10%

T = t

$I = \frac{PRT}{100}$

$I = \frac{845*10*t}{100}$

I = 84.5t

According to question,

Simple interest  on Rs. 750 is less than the interest on Rs. 845 by Rs. 57, therefore

84.5t - 75t = 57

9.5t = 57

t = $\frac{57}{9.5}$

t = 6 years

Hence, the time is 6 years.

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