Question

26. If x+y+z=6(x,y,z> 0) then find the maximum value of xyz.​

Answer 1

given x+y+z=6(x,y,z>0)

We know that for a finite number of terms (real)

A.M ≥ G.M

Consider the terms to be x,y,z

A.M= (x+y+z)÷3=2

G.M= (xyz)^1÷3

2≥(xyz)^1÷3

xyz≤8

The maximum value is 8

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