Question

26) if xsq +1/xsq=27, find (x-1/x)​

Answer 1

Answer:

$(x - \dfrac{1}{x}) = 5$

Step-by-step explanation:

Given that-

$x^{2} + \dfrac{1}{x^{2} } = 27$

$x - \dfrac{1}{x} = ?$

Using formula-

$(x-\dfrac{1}{x})^{2} = x^{2} + \dfrac{1}{x^{2} } - 2(x)(\dfrac{1}{x})$

$(x-\dfrac{1}{x})^{2} = 27 -2(1)$

   = 27 - 2

$(x-\dfrac{1}{x})^{2}=25$

So, $x - \dfrac{1}{x} = \sqrt{25}$

Hence, $(x - \dfrac{1}{x}) = 5$