Question

26. In a GP the 3rd term is 24 and 65 th term is 192. Find the 10'" term .?,??????
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Answer 1

Answer:

Step-by-step explanation:

Here a3 = ar^2 =24 ....(1)

a6 = ar^5 =192 ....(2)

Dividing (2) by (1) we get

ar^5/ar^2 = 192/24

r^3 = 8 = 2^3

r = 2

By substring r = 2 in (1) we get

a = 6.

Therefore a10 = ar^9 = 6(2)^9

= 3072.