26. In a higher secondary school, an inter-school quiz competition was held among 110 students. The
marks obtained by 110 students in an examination are given below:
Marks 1 30–35 35-40 40-45 4 5-50 50-55 55-60 60-65
Number of 14
16 / 28 23
8
3
Students
18
Find the mean.
Answers
The mean marks of the given data of 110 students in an examination is 45.95.
Step-by-step explanation:
For calculating the Mean Marks of the following above given data, let us first calculate certain information from the table in the figure below:
N = ∑f = 14 + 16 + 28 + 23 + 8 + 3 + 18 = 110
∑x.f = (14*32.5) + (16*37.5) + (28*42.5) + (23*47.5) + (8*52.5) + (3*57.5) + (18*62.5) = 455 + 600 + 1190 + 1092.5 + 420 + 172.5 + 1125 = 5055
Therefore,
Mean = [∑f*m] / N = 5055 / 110 = 45.95
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Step-by-step explanation:
Given In a higher secondary school, an inter-school quiz competition was held among 110 students. The marks obtained by 110 students in an examination are given below:
Marks 1 30–35 35-40 40-45 4 5-50 50-55 55-60 60-65
Number of 14 16 28 2318 8 3 Students Find the mean.
- We need to find mean for the given table
- Marks No of students Marks (x) Xf (multiplying x and f)
- 30-35 14 32.5 455
- 35-40 16 37.5 600
- 40-45 28 42.5 1190
- 45-50 23 47.5 1092.5
- 50-55 18 52.5 945
- 55-60 8 57.5 460
- 60-65 3 62.5 187.5
- 110 4930
- We need to find mean from the table.
- So Mean x bar = ∑ xf / ∑ f
- = 4930 / 110
- = 44.8181
- Therefore Mean will be 44.82
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