Question

26. In a mixture of 72 g water and 92 g ethyl alcohol,
calculate the mole fraction for both.
(2019)​

Answer 1

Explanation:

72 g of water means 4 moles of water.

92 g ethyl alcohol means 2 moles of ethyl alcohol.

Mole fraction of water= number of moles of water/total number of moles

Mole fraction of water= 4/4+2= 4/6= 0.66

Mole fraction of ethyl alcohol= 1-0.66= 0.34

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Answer 2

Mole fraction of water is 0.66 moles and mole fraction of ethyl alcohol is 0.34

GIVEN

In a mixture of 72 g water and 92 g ethyl alcohol

TO FIND

Mole fraction of both

SOLUTION

The above problem can be simoly solved as follows;

Mass of water = 72 grams

Moles of water = Given mas/Molar mass

= 72/18 = 4 moles.

Mass of ethyl alcohol = 92 grams

Moles of ethyl alcohol = 92/46 = 2 moles

Total moles = 2 + 4 = 6 moles

Mole fraction of water = Moles of water/Total moles

= 4/6 = 0.66

Mole fraction of ethyl alcohol = 1 - 0.66 = 0.34

Hence, Mole fraction of water is 0.66 moles and mole fraction of ethyl alcohol is 0.34

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