Question

26. In the figure, if <A= <D, then prove that, AE x DC = DE × AF

PLEASE ANSWER!!!​

Answer 1

Answer:

To Prove AE × DC = DE × AF

Step-by-step explanation:

In ΔAFE and ΔDCE,

∠A = ∠D (Given)

∠FEA = ∠CED (Vertically opposite angles)

∴By AA Similarity Rule

ΔAFE ≅ ΔDCE

Now,

By CPST,

AE/DE = AF/DC

∴AE×DC = AF×DE

Answer 2

Answer:

Step-by-step explanation:

In ΔAEF and ΔDCE

∠A = ∠D    [given]

∠AEF = ∠DEC   [vertically opposite angles]

ΔAEF ~ ΔDCE    [AA similarity criterion]

By corresponding parts of similar triangles,

AE/AF = DE/DC

∴AE * DC = DE * AF

HENCE PROVED

Hope it helps