26 ml of a solution of KMnO4 is exactly neutralized by 4.5 grams of anhydrous oxalic acid. Determine the normality of potassium permanganate solution.
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Answer:
Milliequivalents of oxalic acid =50×0.1×2=10
Medium is acidic (∴n=5 for KMnO
4
).
∴ Molarity of KMnO
4
=
5
N
=
5
100
10
=0.02M
In alkaline medium, n=3 for KMnO
4
Hence, normality =0.02×3 =0.06N
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