Chemistry, asked by katha5020, 3 months ago


26 ml of a solution of KMnO4 is exactly neutralized by 4.5 grams of anhydrous oxalic acid. Determine the normality of potassium permanganate solution.

Answers

Answered by chavansanica
0

Answer:

Milliequivalents of oxalic acid =50×0.1×2=10

Medium is acidic (∴n=5 for KMnO

4

).

∴ Molarity of KMnO

4

=

5

N

=

5

100

10

=0.02M

In alkaline medium, n=3 for KMnO

4

Hence, normality =0.02×3 =0.06N

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