26. Prove that :-
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Answers
Answered by
1
LHS
√(1+sinθ)/√(1-sinθ)
=√(1+sinθ)²/√(1+sinθ)(1-sinθ)
=(1+sinθ)/√(1-sin²θ)
=(1+sinθ)/√cos²θ
=(1+sinθ)/cosθ
=1/cos θ +sinθ/cosθ
=secθ+tanθ[proved]
The other one can be solved similarly
√(1+sinθ)/√(1-sinθ)
=√(1+sinθ)²/√(1+sinθ)(1-sinθ)
=(1+sinθ)/√(1-sin²θ)
=(1+sinθ)/√cos²θ
=(1+sinθ)/cosθ
=1/cos θ +sinθ/cosθ
=secθ+tanθ[proved]
The other one can be solved similarly
Answered by
17
Answer:
LHS
√(1+sinθ)/√(1-sinθ)
=√(1+sinθ)²/√(1+sinθ)(1-sinθ)
=(1+sinθ)/√(1-sin²θ)
=(1+sinθ)/√cos²θ
=(1+sinθ)/cosθ
=1/cos θ +sinθ/cosθ
=secθ+tanθ[proved]
The other one can be solved similarly.
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