Math, asked by utkarsh4431, 1 year ago

26. Prove that :-







please answer it fast ​

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Answers

Answered by saumik61
1
LHS
√(1+sinθ)/√(1-sinθ)
=√(1+sinθ)²/√(1+sinθ)(1-sinθ)
=(1+sinθ)/√(1-sin²θ)
=(1+sinθ)/√cos²θ
=(1+sinθ)/cosθ
=1/cos θ +sinθ/cosθ
=secθ+tanθ[proved]
The other one can be solved similarly

utkarsh4431: thanks
Answered by Anonymous
17

Answer:

LHS

√(1+sinθ)/√(1-sinθ)

=√(1+sinθ)²/√(1+sinθ)(1-sinθ)

=(1+sinθ)/√(1-sin²θ)

=(1+sinθ)/√cos²θ

=(1+sinθ)/cosθ

=1/cos θ +sinθ/cosθ

=secθ+tanθ[proved]

The other one can be solved similarly.

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