Question

26 sum urgent pls help

Answer 1

let ∆ABC is given.

so side AB=15x

side BC=13x

side AC=14x

perimeter=168=AB+BC+AC

168=15x + 13x +14x

so we get x=4

put the value of x in all side

we get AB=60

BC=52

AC=56

and we get S=AB+BC+AC/2

=52+56+60/2
=84

area =√S(S-AB)(S-BC)(S-AC)

=√84(84-52)(84-56)(84-60)

=√84(32)(28)(24)

=1344.00

Answer 2

We know that sum of sides of a triangle = perimeter

Now, since the sides are in ratio 15:13:14,

Let the sides be 15x , 13x , 14x respectively.

Adding these sides, we get perimeter

15x + 13x + 14x = 168

42x = 168

x= $\frac{168}{42}$

x= 4

therefore, we get the sides as,

15 x 4= 60cm

13 x 4 = 52cm

14 x 4 = 56cm

Since we have all the sides now, we can find the area of the triangle by applying Heron's formula

first, s = $\frac{a+b+c}{2}$

s = $\frac{60+52+56}{2}$

s = 84

now applying Heron's formula,

S = $\sqrt{s(s-a)(s-b)(s-c)}$

S = $\sqrt{84(84-60)(84-56)(84-56)}$

S = $\sqrt{84  X  24  X  28  X  32}$

S = $\sqrt{1806336}$

S = 1344 $cm^{2}$