Question

(26. द्विघाती सूत्र से मूल ज्ञात कीजिए।
3x2-5x + 2 = 0​

Answer 1

3x²-5x+2

=3x²-3x-2x+2

=3x(x-1)+2(x-1)

=(x-1)(3x+2)

Either

x-1=0

=>x=1

Or

3x+2=0

=>3x= -2

=>x= -2/3

Hope it helps...

please mark as brainliest....

Answer 2

Step-by-step explanation:

3x²-5x + 2 = 0

3x²-3x-2x+2=0

3x(x-1)-2(x-1)=0. p=3×2

(x-1)(3x-2)=0. =6

(x-1)=0 or (3x-2)=0. s=-5

x=1 or 3x=2. no.=-3,-2

x=1 or x=2/3

the roots of equation is 1 and 3/2.