Question

26. The distance of the point P(–6, 8) from the origin is a) 8 units b) √7 units c) 10 units d) 6 units​

Answer 1

Answer:

Solution

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Correct option is

C

10

ThedistancepofapointP(x,y)fromtheorigineisp=x2+y2.HereP(x,y)=(6,8).∴p=x2+y2=62+82units=100units=10units.Ans−10units.

solution

Step-by-step explanation:

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Answer 2

To Find :- The distance of the point P(–6, 8) from the origin is :-

a) 8 units b) √7 units c) 10 units d) 6 units

Formula used :-

• Coordinates of origin = (0, 0)
• The distance between points A(a, b) and B(c, d) is equal to :- √[(a - c)² + (b - d)²] = √[(c - a)² + (d - b)²]

Solution :-

Comparing given points P(-6, 8) and origin (0, 0) with A(a, b) and B(c, d) we get :-

• a = (-6)
• b = 8
• c = 0
• d = 0

So,

→ Required distance = √[(a - c)² + (b - d)²]

→ Required distance = √[(-6 - 0)² + (8 - 0)²]

→ Required distance = √[(-6)² + (8)²]

→ Required distance = √[36 + 64]

→ Required distance = √(100)

→ Required distance = √(10)²

→ Required distance = 10 units (C) (Ans.)

Hence, the distance between given point P and origin is equal to 10 units.

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