Question

26.
The PE of a 2 kg particle. free to move along
x-axis is given by V(x) =[(x^3/3)-(x^2/2)]
J. The total
mechanical energy of the particle is 4 J. Maximum
speed (in ms') is​

Answer 1

Answer (5/root6)

Explanation:

Answer 2

Answer:

Answer is 5/√6

Explanation:

just see the uploaded photo