26.
The PE of a 2 kg particle. free to move along
x-axis is given by V(x) =[(x^3/3)-(x^2/2)]
J. The total
mechanical energy of the particle is 4 J. Maximum
speed (in ms') is
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Answered by
43
Answer (5/root6)
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Answered by
8
Answer:
Answer is 5/√6
Explanation:
just see the uploaded photo
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