26.
The perimeter of two similar triangles are 30cm and 20cm respectively. If one side of the first
triangle is 12cm, then the corresponding side of the second triangle is in cm
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Answer:
Let △ABC and △DEF be two similar triangles of perimeters P
1
and P
2
respectively.
Also, let AB=12 cm, P
1
=30 cm and P
2
=20 cm.
Then,
DE
AB
=
EF
BC
=
DF
AC
=
P
2
P
1
[∵ Ration of corresponding sides of similar triangles is equal to the ratio of their perimeters]
⇒
DE
AB
=
P
2
P
1
⇒
DE
12
=
20
30
⇒ DE=
30
12×20
cm=8cm
Hence, the corresponding side of the second triangle is 8 cm
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