Question

26.The population of a city is 400000 . If it increases at the rate of 10% per
annum, find the population of the city after two years.

Answer 1

Answer:

Given current population = 4,00,000

Increases rate = 10%

now

population in first year = 4,00,000*10/100

= 40,000

so in 1 year population is = 4,00,000 + 40,000

= 4,40,000

now

population of 2nd year = 4,40,000*10/100

= 44,000

now total population = 4,40,000 + 44,000

= 4,84,000

hope this helps you