Question

26. The population of a town increases 10% annually. If its present
will be its population after 2 years?​

Answer 1

Answer:

Mate u have not given present population.

How would I calculate??

Step-by-step explanation:

Answer 2

Present population = 60000
(As you haven’t given the present population, I’ve assumed it to be 60,000 because I have a question like this and in that the present population is 60,000. If it is wrong, u can substitute the value of 60000 and write the value according to your book.)

For 1st year,
Increase = 10%
= 10% of 60000
= 10/100 x 60000
= 6000
Therefore, population after 1st year = 60000 + 6000 = 66000

For 2nd year,
Increase = 10%
= 10% of population after 1st year
= 10/100 x 66000
= 6600
Therefore, population of the town after 2nd year = 66000 + 6600
= 72600

Hence, population of town after 2 years = 72,600

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