Math, asked by akulbisht78900, 9 months ago

26. The present age of father is four times the age of his son. After 10 years, age of father will become three times the age of his son. Find their present ages. I want full calculation

Answers

Answered by Avi10438
0

Step-by-step explanation:

Let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20

Answered by pranab3745
1

Step-by-step explanation:

let the age of son be x

then the age of his father 4x

A T Q

4X +10=3(X+10)

4X+10 = 3X+30

4X-3X=30-10

X=20

THEREFORE,AGE OF SON IS 20YRS AND HIS FATHER IS 80YRS

Similar questions