Chemistry, asked by holyshit10, 7 months ago

26. The structure of IV in the following sequence is:
AgCN
H/Ni
CH3COCI/ pyridine
HBr
IV
CH2
(C6H5COO)2
CH3
NHCOCH3
NHCOCH3
COCH3
CH2NCH
CH3 COCH3
NCH3
H₂O
I
CH3
CH3
H3C CH3
3
1
2​

Answers

Answered by anitakumari0688
5

Answer:

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