Math, asked by dks3586, 4 days ago

26) The sum of the ages of Anup and his father is 100. When Anup is as old as his father he will be five times as old as his son Anuj is now. Anuj will be eight years older now, than Anup is now, when Anup is as old as his father. What are their ages now? ​

Answers

Answered by astujsingh11
1

Answer:

Anup is 35 years old, Anup's father is 65 years old

and Anuj is 13 years old

Step-by-step explanation:

Let Anup's age be A and Anup's father's age = F. Then A + F = 100.

Father's age F = 100 - A.

When Anup is as old as his father, his age will be (100 - A).

Difference between Anup's age now and then = (100 - A) - A = (100 - 2A).

Hence Anup will reach his father's age after (100 - 2A) years.

Anuj's age now = (1/5) of Anup's age when his age equals his father's age                       = (100 - A)/5.

Anuj's age when Anup attains his father's age,i.e., after (100 - 2A) Years = [(100 - A)/5] + (100 - 2A).

This age is 8 years more than Anup's age now,i.e., 8 more than A = A + 8.

Hence [(100 - A)/5] + (100 - 2A) = A + 8

Solving, Anup's age A = 35, Anup's father's age F = 65, Anuj's age = (100 - 35)/5 = 13

Hope it helps!!!

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